Volumes of Solids of Revolutions Help

jzsc
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Homework Statement



Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the region, the solid, and a typical disk or washer.

y=x, y=0, x=2, x=4; about x=1


The Attempt at a Solution


one of the radii is x=y but I am not sure how to find the other one and the interval? Please explain this one to me. Thanks!
 
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jzsc said:

Homework Statement



Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the region, the solid, and a typical disk or washer.

y=x, y=0, x=2, x=4; about x=1

The Attempt at a Solution


one of the radii is x=y but I'm not sure how to find the other one and the interval? Please explain this one to me. Thanks!
Hello jzsc. Welcome to PF !

Which are you using, the disk method or the washer method ? Until you decide that, you can't specify a radius.
 
thank you SammyS! I am using the washer's method
 
2\Pi\int x f(x) dx

The x is serving as the distance from the y-axis (the radius), so if you're rotating around x=1 rather than x=0...

(I don't know how to put the a & b above and below the integrand)
 
Last edited:
e^(i Pi)+1=0 said:
2\Pi\int x f(x) dx

(I don't know how to put the a & b above and below the integrand)

2\Pi\int_a^b x f(x) dx

ehild
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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