Water & Electrolyte: How Does it Work?

  • Thread starter Thread starter thedy
  • Start date Start date
  • Tags Tags
    Water
Click For Summary
Water is not a good conductor in its pure form, with ultrapure water exhibiting high resistance of 18 MΩcm. Its conductivity primarily arises from contaminants that introduce ions into the water. While water lacks free electrons like metals, it can conduct electricity through the movement of ions, which transfer charge within the solution. The process of conduction involves ions moving in bulk, while reduction and oxidation occur at electrodes, facilitating charge transfer. Understanding these mechanisms clarifies how water can conduct electricity despite its initial properties.
thedy
Messages
77
Reaction score
0
I have no idea why water is good conductor.Water has not a lot of freee electrons.Yes water has ions,but theoretically,if I catch a wire under current and I stay in water what is going on with ions?They cannot go through body.Only electrons.So how is it possible?
 
Physics news on Phys.org
Water is not a good conductor, quite the opposite. Ultrapure water has a specific resistance of 18 MΩcm

Then, water gest very easily contaminated and it is presence of ions from contamination that makes it conductive.

--
 
Borek said:
Water is not a good conductor, quite the opposite. Ultrapure water has a specific resistance of 18 MΩcm

Then, water gest very easily contaminated and it is presence of ions from contamination that makes it conductive.

--
buffer calculator, concentration calculator
pH calculator, stoichiometry calculator
Yes,I know that ions makes water good conductor,but I don t understand the process of this.I metals are free electrons,but water not.And ions cannot be oxidise or reduce,because there aren t any electrodes like for example in the battery.So my question is,what exactly conducts electric current.Some graph or something will be welcome.THanks again
 
Moving ions transfer charge in bulk of the solution, reduction/oxidation on electrodes transfers charge through the phase border.

--
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
15
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
525
  • · Replies 12 ·
Replies
12
Views
2K