- #1

joshmccraney

Gold Member

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## Main Question or Discussion Point

Hi PF!

Suppose I have a square tank of water. If I drive the tank of water such that it's height as a function of time is ##h(t) = \cos(t)##, ignoring gravity, is this the same thing as saying the tank is holding still but the pressure field is changing as ##p(t)=\cos(t)##?

Suppose I have a square tank of water. If I drive the tank of water such that it's height as a function of time is ##h(t) = \cos(t)##, ignoring gravity, is this the same thing as saying the tank is holding still but the pressure field is changing as ##p(t)=\cos(t)##?