A siphon is used to empty a large vessel of water (see picture). Calculate/state the intial (absolute) pressures at points 0, 1, 2, 3, 4 and 5.(adsbygoogle = window.adsbygoogle || []).push({});

http://img499.imageshack.us/img499/8104/siphon1oq.th.jpg [Broken]

P0 = 1.013 x 10^5 Pa - the pressure exerted on the water by the atmosphere

P1 = Po + density x gravity x height of water

P2 = Po + density x gravity x height of water

The answer for pressure at point 3 is 1.013x10^5 Pa but I'm not sure why that is.

P4 = P3 - density x gravity x height of water

P5 = 1.013 x 10^5 Pa - the minimum pressure required to overcome atmospheric pressure.

Could someone please explain the pressure at point 3 for me?

Thanks

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# Homework Help: Water Pressure problem

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