Wave Composition - Different Amplitudes

AI Thread Summary
The discussion focuses on the superposition of two waves with different amplitudes and how to analyze their behavior at a specific location. The user struggles with combining the wave equations due to the differing amplitudes and seeks clarification on the resulting beat frequency. It is established that the beat frequency can be determined by the difference in frequencies of the two waves, regardless of their amplitudes. The user concludes that the beat frequency is consistently equal to the difference between the two frequencies, confirming that this principle holds true. Overall, the conversation emphasizes the relationship between wave amplitude, frequency, and beat behavior.
bobthenormal
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Homework Statement



The superposition of two waves, [see attachment - it doesn't let me link the attachment because I'm new ;P] at the location x = 0 in space results in what kind of wave behavior? [As in, how often does it beat and what frequency is the sound?]

Homework Equations



Wave equations are given, general form is: Acos(kx-wt).

k = 2pi/lamda; w = 2pi/T = 2pi*f

The Attempt at a Solution



This is troublesome because I'm not sure how to work with the different amplitudes. I can't think of a way to add them, because of the different amplitudes I can't factor and get a trig identity that is easy to work with.

Essentially I have: A cos(at) + B cos(bt)

But I can rewrite it as: A cos(at) + B cos(at-ct)

= A cos(at) + B ( cos(at)cos(ct) - sin(at)sin(ct) )

= cos(at)(A + B cos(ct)) - B sin(at)sin(ct)

...etc. It just gets uglier.

Any help on this would be greatly appreciated.. although, I'm going to sleep right now, I'll be up in a few hours.

--Bob
 

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The only modification i can think of that helps a bit is:
A cos(at) + B cos(bt) = (A-B) cos(at) + B cos(at) + Bcos(bt) =
(A-B)cos(at) + 2*B cos((at-bt)/2) cos((at+bt)/2)

from where you can see a few things such as the frequency of the sound is roughly (a+b)/2 assuming a is close to b, frequency of the beats is a-b, because of the symmetry and max and min amplitudes of the beats are A+B and A-B respectively.
 
Argh, sorry, I don't know how you got the max and min amplitudes being separated by an a-b beat from that equation? Can you explain it a bit more? I kind of see it... but... 2Bcos((a-b)t/2)cos((a+b)t/2) + (A-B)cos(at) seems less friendly than the original equation to me... the 2B with double cos terms are a bit confusing to try to visualize.

I did realize by thinking of the phase difference, that the composition of the beat must have a 6 Hz frequency because of the relation of period and frequency... the beat obviously has a maximum at t=0, so I just have to find the next beat crest. The amount the waves become out of phase increases by increments of (1/150 - 1/156), so they come into phase every (1/150 - 1/156) seconds, which is 6 Hz. - so, is this f_beat = f_1 - f_2 always true regardless of amplitude differences? The book I have doesn't say anything about beating with different amplitude waves, so I'm not sure.

--Bob
 
You may look on it as a superposition of a standard 2*B amplitude beat wave and harmonic wave with constant amplitude A-B, if you imagine only the envelopes of these waves it becomes clear that the envelope of the superposed wave is the sum of them.

is this f_beat = f_1 - f_2 always true regardless of amplitude differences?

It is.
beats.png
 
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