Wave equation in inhomogeneous media -- Question about the formula

Click For Summary
SUMMARY

The discussion focuses on the derivation of the wave equation in inhomogeneous media, specifically addressing the term ε0/ε. The equation presented is ∇ × H = ∂D/∂t, where D is defined as D = ε(r)E. This leads to the reformulation of the equation as (1/ε(r))∇ × H = ∂E/∂t, which is further manipulated to derive ∇ × [(1/ε(r))(∇ × H)] = -μo ∂²H/∂t². The relationship εoμo = 1/c² is also highlighted, establishing a connection between permittivity, permeability, and the speed of light in the medium.

PREREQUISITES
  • Understanding of Maxwell's equations
  • Familiarity with electromagnetic wave propagation
  • Knowledge of material properties like permittivity (ε) and permeability (μ)
  • Basic calculus and differential equations
NEXT STEPS
  • Study the derivation of Maxwell's equations in different media
  • Learn about the physical significance of ε(r) in electromagnetic theory
  • Explore the implications of inhomogeneous media on wave propagation
  • Investigate the relationship between εo, μo, and the speed of light (c)
USEFUL FOR

Physicists, electrical engineers, and students studying electromagnetic theory, particularly those interested in wave propagation in complex media.

macabre
Messages
6
Reaction score
0
Engineering news on Phys.org
Well, the first equation is,

##\nabla \times H = \frac{\partial D}{\partial t}##

to which we note, ##D = \epsilon(r)E## to get,

##\frac{1}{\epsilon(r)}\nabla \times H = \frac{\partial E}{\partial t}##

so,

##\nabla\times[\frac{1}{\epsilon(r)}(\nabla\times H)] = -\mu_o \frac{\partial^2 H}{\partial^2 t}##

where we've snuck in ##B=\mu_o H##. Multiply both sides by ##\epsilon_o## and note that ##\epsilon_o \mu_o = \frac{1}{c^2}##
 
  • Like
Likes   Reactions: macabre
Thank you :smile:
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
8
Views
4K
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 23 ·
Replies
23
Views
2K