- 6,962
- 6,040
b.shahvir said:The above principle applies to motional emfs (dynamically induced), not transformer emfs (rate of change of flux)
What are you talking about? This is extraordinarily incorrect. Please provide references.
b.shahvir said:The above principle applies to motional emfs (dynamically induced), not transformer emfs (rate of change of flux)
The principle is one: Faraday's law of induction. It can be used for motional emf and transformer emf.b.shahvir said:The above principle applies to motional emfs (dynamically induced), not transformer emfs (rate of change of flux)
Delta2 said:The principle is one: Faraday's law of induction. It can be used for motional emf and transformer emf.
hutchphd said:What are you talking about? This is extraordinarily incorrect. Please provide references.
You got it wrong, because the magnetic field is homogeneous, it doesn't necessarily mean that the rate of change of flux is 0. Please check the principle of AC sinusoidal voltage generation. There you have a homogeneous magnetic field and a rotating coil.b.shahvir said:The magnetic field in close proximity to the poles is homogeneous, hence rate of change of flux is 0 at this position
The transformer, like an ac generator, also works according to Faraday's law ## \mathcal{E}=-\frac{d \Phi}{dt} ##.b.shahvir said:Please explain me relation of homogeneous magnetic fields with statically induced emfs (transformer principle)
Charles Link said:When the axis of the magnet is aligned with the normal to the plane of the coil, the magnetic flux is at a maximum. It is not a matter of being homogeneous here. When the flux has a peak,(in absolute value), it is simple calculus to see that ## \mathcal{E}=-\frac{d \Phi}{dt}=0 ##.
It can help considerably to have a thorough mathematics background when analyzing some of the scenarios that appear in these E&M problems. In this case ## \Phi=\Phi(\theta) ## and the function ## \Phi ## peaks on-axis. By the chain rule, ## \frac{d \Phi}{dt}=(\frac{d \Phi}{d \theta})( \frac{d \theta}{dt}) ##. When a (well-behaved) function has a peak, its derivative is zero at that point. This does not require a uniform field. In this case, it is a very narrow peak, and not a broad peak, so the zero of the derivative is present for only an instant, instead of being more prolonged.b.shahvir said:I have attempted to explain the same in practical context. Although the magnet is in motion, the induced emf is 0 as rate of change of flux linkage is 0 due to homogeneity of the magnetic field at that instant.
Yes in this example the homogenity of the field is what causes the induced emf to be zero. However it is not the same as the rotating magnet. There the emf becomes zero because the flux comes to a maximum as @Charles Link very successfully said at post #129. The flux comes to a maximum because if we do the math we can see that the flux depends on the cosine of the angle between the magnet axis and the coil axis, and this cosine is at maximum(=1) when the angle becomes zero i.e magnet axis align to the coil axis.b.shahvir said:Consider an hypothetical case of a bar magnet emanating an homogeneous magnetic field in all directions around it upto infinity. This implies that the magnetic field strength around this magnet does not change with distance upto infinity.
Now consider faraday's simple magnet and coil experiment. I will consider the coil to be wound on a ferromagnetic core for greater effectiveness. Now place this bar magnet along the axis of the coil at a finite distance from the face of the coil. Now move the magnet towards the coil with constant velocity.
It will be observed that the change in magnetic field strength will be 0 (homogeneous field) although the magnet is in continuous motion. In other words, the rate of change of flux linking the coil be 0, hence the induced emf in the coil will also be 0.
Delta2 said:Yes in this example the homogenity of the field is what causes the induced emf to be zero. However it is not the same as the rotating magnet. There the emf becomes zero because the flux comes to a maximum as @Charles Link very successfully said at post #129. The flux comes to a maximum because if we do the math we can see that the flux depends on the cosine of the angle between the magnet axis and the coil axis, and this cosine is at maximum(=1) when the angle becomes zero i.e magnet axis align to the coil axis.
The coil does not know that the field is uniform near the pole of the magnet either.b.shahvir said:Mathematically yes, but my explanation was pertaining to physical concept. The coil does not know mathematics, the coil
is not living thing to know that when the flux is maximum I need to reduce my emf to 0. So why does the emf become 0? Because in that position there is no further change in magnet field strength due to uniformity of the field near the pole tips at that particular instant in time. So in the absence of change of flux wrt time, the emf induced in the coil is 0. This is in purely physical context.

Delta2 said:The coil does not know that the field is uniform near the pole of the magnet either.
Delta2 said:I think your intuition tells you that is because of the uniformity of the field and you insist on your intuition. However when we do the math we get a different explanation, between your intuition and the math i choose what math say. Sorry!![]()
Delta2 said:There the emf becomes zero because the flux comes to a maximum as @Charles Link very successfully said at post #129. The flux comes to a maximum because if we do the math we can see that the flux depends on the cosine of the angle between the magnet axis and the coil axis, and this cosine is at maximum(=1) when the angle becomes zero i.e magnet axis align to the coil axis.
It can be said that the coil solves mathematical equations, that's how analog computers used to work.b.shahvir said:As a matter of fact, how does the coil know the flux has attained maximum value and will not change further? How will it sense it? I don't think it will resort to solving mathematical equations
Delta2 said:It can be said that the coil solves mathematical equations, that's how analog computers used to work.
The laws of physics are better expressed in the language of mathematics. A qualitative /intuitive approach is always good but sometimes it leads us to the wrong conclusions and such is the case here.
The coil doesn't need to know anything as you said, it just obeys the laws of physics and mathematics. The laws of physics tell us that the induced EMF is the first derivative (with respect to time) of the magnetic flux. The laws of mathematics tell us that this first derivative become zero when the function, that is the magnetic flux attains a maximum (or a minimum). It doesn't need to remain constant to maximum just to attain a maximum at an instant in time. The laws of math also tell us that this function of magnetic flux attains a maximum when the angle between the magnet axis and the coil axis becomes zero.b.shahvir said:Ok I maybe wrong for the sake of argument, but please make me understand analytically how the coil knows that the magnetic field has attained maximum value and there will be no further change in its strength at that instant.
Delta2 said:The coil doesn't need to know anything as you said, it just obeys the laws of physics and mathematics. The laws of physics tell us that the induced EMF is the first derivative (with respect to time) of the magnetic flux. The laws of mathematics tell us that this first derivative become zero when the function, that is the magnetic flux attains a maximum (or a minimum). It doesn't need to remain constant to maximum just to attain a maximum at an instant in time. The laws of math also tell us that this function of magnetic flux attains a maximum when the angle between the magnet axis and the coil axis becomes zero.
Well kind of agreed to that, my answer is based on a mathematical understanding of the physical laws, rather than on a qualitative /intuitive understanding of the physical laws.b.shahvir said:Your response is still mathematical and not analytical.
Delta2 said:Well kind of agreed to that, my answer is based on a mathematical understanding of the physical laws, rather than on a qualitative /intuitive understanding of the physical laws.
Post the movie elsewhere and give a link in your PF post. YouTube works.Tom.G said:Anyone have a fix or any clues?
I very much agree with this. A slight negligence or lack of careful thinking due to laziness makes it easy to draw wrong conclusions based on intuitive analysis. I have made this mistake before. Intuition leads me to believe that when the poles are to the sides, and equidistant from the coil, the rate of change of magnetic flux should be zero, but this is not the case.Delta2 said:A qualitative /intuitive approach is always good but sometimes it leads us to the wrong conclusions and such is the case here
Fortunately, Charles Link's excellent analysis post #107 quickly pointed out this misunderstanding.Charles Link said:The voltage is caused by the time derivative of the flux. When the poles are to the sides, and equidistant from the coil, the total flux is zero, but the derivative can be near maximum. This is where you observe the slight dip between the peaks, which occur just before and just after this position
alan123hk said:I very much agree with this. A slight negligence or lack of careful thinking due to laziness makes it easy to draw wrong conclusions based on intuitive analysis. I have made this mistake before. Intuition leads me to believe that when the poles are to the sides, and equidistant from the coil, the rate of change of magnetic flux should be zero, but this is not the case. Fortunately, the excellent analysis of post #107 quickly pointed out this misunderstanding.
View attachment 284412
Charles Link said:The rotating pole magnet version makes for a good laboratory demonstration, but because of the distorted sinusoids, as well as the very incomplete flux coupling, that geometry is generally not used in commercial electrical generators
Yes. If the magnet is completely immersed in a uniform magnetic field while rotating. By a uniform magnetic field, I refer to one that is generated by, for example, a Helmholtz coil when the coil is energized by a constant current. In this case, the generated EMF by a spinning magnet is exactly a sinusoid. The generated EMF is related to the volume integral of a constant B field dotted with the magnetization. The only time dependence comes from the direction of the magnetization, which is a pure sinusoid in time.b.shahvir said:Can I generate a perfect sinewave if I use a cylindrical dipole magnet as rotor? The experimental results with such an arrangement will be quite interesting.