Wavelength in an electron transition

AI Thread Summary
A 4p to 4s electron transition in sodium is allowed due to the change in angular momentum quantum number (Δl = 1). The energy difference calculation using the formula E_n = -13.60/n² leads to confusion, as the values for n do not yield a meaningful result for this transition. The wavelength can be determined using λ = 1240 eV nm / ΔE, but the user struggles to find ΔE. The final answer for the wavelength is 2.21 μm, indicating that the transition is indeed valid. Further resources on effective nuclear charges for sodium are suggested for clarification.
elephantorz
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1. Is a 4p -> 4s transition allowed in sodium? If so, what is the wavelength? If not, why not? (Z = 11 for sodium)



2. \Deltal = |l2 - l1| = 1
That is for the first question, in which case it is allowed, hence |0-1| = |-1| = 1, and meets the requirements for the equation.

The second part is what I don't understand because I used these equations:
E_{n} = \frac{-13.60}{n^{2}}eV
n = 1, 2, 3, ...


Next I used:
\DeltaE_{atom} = E_{1} - E_{2} = 0

Meaning, I get zero for this because of the repeating n = 4, then 4^{2} which = 16 and therefore I have an issue here I do not know how to solve after pondering.

The third equation I must use is:
\lambda = 1240 eV nm / \DeltaE

But I am not there yet...


3. As you can see my attempt is either erroneous or there is some sort of lone energy I am not aware of, by the way, the answer to this is:

Yes; 2.21 \mum

Thank you.
 
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Ummm... Are you sure it is 4p to 4s? Double check what is written.
 
nickjer said:
Ummm... Are you sure it is 4p to 4s? Double check what is written.

I did, three times...I guess I will just have to lose points for this.
 
Is there a table in your book of the orbital dependence of the energy in sodium?
 
Here is an equation that uses different effective nuclear charges depending on the orbital quantum number:

http://physics.wm.edu/~inovikova/phys251/manual/naspec.pdf
 
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