What is the Energy Ratio of Two Photons with Different Wavelengths?

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To find the energy ratio of two photons with different wavelengths, use the equation E = hc/λ, where E is energy, h is Planck's constant, and c is the speed of light. The first photon has a wavelength of 6770 nanometers, while the second photon has a wavelength that is 1/6 of that, which is approximately 1128.33 nanometers. The energy of the second photon will be greater due to its shorter wavelength. The ratio of the energy of the second photon to the first photon can be calculated without needing the exact wavelengths, focusing instead on their relationship. Understanding this ratio is crucial for applications in quantum physics and photonics.
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Homework Statement



Suppose one photon has a wavelength of 6770 nanometers while a second photon has a wavelength 1/6 as large. What is the ratio of the energy of the second photon divided by the first photon?



Homework Equations



Not sure.



The Attempt at a Solution



Don't know where to start.
 
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Try one step at a time. What is the wavelength of the second photon?
 
E = hc/λ

You don't even need the wavelengths.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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