Wavelength Q: Train Speed 40m/s, Horn 320Hz

  • Thread starter Thread starter TbbZz
  • Start date Start date
  • Tags Tags
    Wavelength
AI Thread Summary
A train traveling at 40.0 m/s emits a horn sound at 320 Hz, leading to a discussion on the frequency change detected by an observer as the train approaches and recedes. The frequency detected while approaching is calculated to be 282 Hz, while it decreases to 357.1 Hz when receding, indicating a change of -74.2 Hz. Participants clarify that the speed of sound (345 m/s) should be used in calculations instead of the train's speed. The correct formula for frequency change is confirmed as f1 = f((v + v[observer])/(v - v[source of sound])). The discussion emphasizes the importance of understanding the Doppler effect in sound frequency perception.
TbbZz
Messages
37
Reaction score
0

Homework Statement



A train passes a person at a constant speed of 40.0m/s. The train horn is sounded at its characteristic frequency of 320 Hz.

Homework Equations



a) What overall change in frequency is detected by the person as the train moves from approaching to receding?

b) What wavelength is detected by the person as the train approaches?

The Attempt at a Solution



I already solved A. I got a change of -74.2 Hz. 282Hz for approaching and 357.1Hz for receding.

I have absolutely no idea how to do part B. I tried using V = "lambda"f (a.k.a. velocity = wavelength * frequency) but it didn't work.
 
Physics news on Phys.org
No, you did the right thing. What didi you use for v? The speed of sound, right? (Not the speed of the train, eh?) What numbers did you use and what answer did you get?
 
Heh, I was using the speed of the train, thanks for that.

however I'm using the speed of sound for V (345 m/s) and for frequency I'm using 282.9, I'm getting the wrong answer.
 
Last edited:
I thought if it's approaching, I use +/- and when receding I use -/+
 
I don't know exactly what equation you are using, but I worked it out and I get different answers than you do for (a).
Think of car horn as you are standing on the side of the street. As it comes towards you, it makes a higher pitch than when it moves away from you. So the frequency must increase as it moves towards you for that to happen. Conversely, for the pitch to be lower as it moves away from you, the frequency must decrease.
 
What equation am I supposed to be using?

I'm using f1 = f((v + v[observer])/(v - v[source of sound])).

I understand the concept of a higher frequency occurring when you are closer to the source, but the formula just isn't working out that way.
 
That's the right equation for when the train is approaching the observer, with v=345m/s and v[observer]=0. You are solving for f1, right?

I don't know, it works for me!
 
Back
Top