Weight on a pulley, torque, mechanical energy

AI Thread Summary
The discussion centers on calculating the speed of a block attached to a pulley after falling a height h, using conservation of mechanical energy principles. The relevant equation incorporates gravitational potential energy and kinetic energy for both the block and the pulley. The moment of inertia for the pulley is correctly identified as (1/2)(m2)R^2. The final expression for the block's speed is derived as v = sqrt[(m1gh) / (0.5(m1) + 0.25(m2))]. The solution is confirmed to be correct.
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Homework Statement


A block of mass (m1) is attached by a massless string to a pulley of mass (m2) with radius R. Starting from rest, what is the block's speed after it has fallen height h?

Homework Equations


I'll call angular velocity w.
I'm thinking conservation of mechanical energy, so (m1)gh = (1/2)(m1)v^2 + (1/2)Iw^2
Moment of inertia for the pulley would be (1/2)(m2)r^2

The Attempt at a Solution



(m1)gh = (1/2)(m1)v^2 + (1/2)[(1/2)(m2)r^2](v^2/r^2)
simplifying would give
v=sqrt[(m1gh) / (.5(m1) + .25(m2))]

Is this right?
 
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Yes.

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