- #1
TitoSmooth
- 158
- 6
Y=x^(2/3) and y=x^2 rotated about the x=4.
First I equate the equations giving me x=0,-1,1. The problem is I have exactly 2 graphs that are symmetric in respect to the y axis. N I have not encountered a problem in stewart dealing with this.
I know that the volume on the right side of the X axis is going to be. 2pie∫(4-x)(x^2-x^(2/3)) dx. And the limits of integration are from 0 to 1.
What about the side left from origin?
After I find the integral for both of the areas. Do I right of origin- left of origin or right of origin +LEFT of origin?
Thanks
First I equate the equations giving me x=0,-1,1. The problem is I have exactly 2 graphs that are symmetric in respect to the y axis. N I have not encountered a problem in stewart dealing with this.
I know that the volume on the right side of the X axis is going to be. 2pie∫(4-x)(x^2-x^(2/3)) dx. And the limits of integration are from 0 to 1.
What about the side left from origin?
After I find the integral for both of the areas. Do I right of origin- left of origin or right of origin +LEFT of origin?
Thanks