Weird thinking of electric field inside a hollow cylinder.

AI Thread Summary
The discussion centers on the electric field inside a hollow cylinder, where it is established that the electric field is zero for a long cylinder. A participant expresses confusion about this concept, particularly regarding the behavior of a positive charge placed off-center within the cylinder. The explanation provided clarifies that contributions to the electric field from different segments of the cylinder cancel each other out due to symmetry, even when considering off-center positions. This cancellation occurs because the electric field contributions from small arcs of charge are antiparallel and equal in magnitude. Ultimately, the discussion reinforces the understanding of electric field behavior in symmetrical charge distributions.
TwoEG
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While I was studying with electric field about cylinder, I learned that for a very long cylinder, the electric field in the hollow of cylinder will be zero.

http://physics.stackexchange.com/questions/156789/electric-field-of-hollow-cylinder

However, I couldn't accept this intuitively, and thought up this weird idea.

We can express electric field E of charged line like

##E=\frac \lambda {2\pi\epsilon_0 r}##

Thus, we knows that (+) charge between two parallel lines with same charge density will always move to their center, right?

Then, suppose we have a (+) charge in a cylinder other than on its axis, and let's see that cylinder above from it.

1.png


And this is what really confuses me.

2.png


Draw a line that passes charge, then it'll meet with circle(cylinder) at two points(lines). Since a red dot(line) is always closer than a blue dot(line), sum of all forces will head to the left(?).

3.png


But this weird calculation conflicts with the fact that E=0 in the hollow of the cylinder.

What is a critical mistake of this logic(?). Will it be possible to explain why this image is wrong without using exact calculation?
 
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It is good that you worry about this. The critical mistake in the logic is this. Imagine two intersecting lines crossing at your off-center point. They define a blue arc dsblue and a red arc dsred. We make the ds arcs very small, not like in your figures, so that the contributions to the E-field from each arc are antiparallel and can be treated as contributions from lines of charge . The charge on each arc is proportional to ds, so that the magnitude of its contribution to the E-field is $$ dE \sim \frac{ds}{r} = \frac{r d \theta}{r} = d \theta $$ Since the subtended angle by the two arcs is the same, the fields cancel. This argument is similar to the 3d argument for the electric field inside a uniformly charged shell, except there one uses solid angles.
 
kuruman said:
It is good that you worry about this. The critical mistake in the logic is this. Imagine two intersecting lines crossing at your off-center point. They define a blue arc dsblue and a red arc dsred. We make the ds arcs very small, not like in your figures, so that the contributions to the E-field from each arc are antiparallel and can be treated as contributions from lines of charge . The charge on each arc is proportional to ds, so that the magnitude of its contribution to the E-field is $$ dE \sim \frac{ds}{r} = \frac{r d \theta}{r} = d \theta $$ Since the subtended angle by the two arcs is the same, the fields cancel. This argument is similar to the 3d argument for the electric field inside a uniformly charged shell, except there one uses solid angles.

Thanks for cool explanation! They are canceling out each other so clearly... awesome!
 
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