Solving for Angle of Vector: Ball Bouncing Problem | Physics Homework Help

  • Thread starter Thread starter nc1617
  • Start date Start date
  • Tags Tags
    Angle Vector
AI Thread Summary
A ball is tossed, bounces off the ground, and rises to a height of 3.10 m before landing 0.70 m away. The vertical velocity (Vy) was calculated as approximately 7.799 m/s, while the horizontal velocity (Vx) was determined to be 0.441 m/s. The angle of the vector was initially calculated using the inverse tangent function but was found to be incorrect. The correct formula for the angle is tan(θ) = Vy/Vx, leading to a revised calculation for the angle. The discussion emphasizes the importance of using the correct relationship between vertical and horizontal components to find the accurate angle.
nc1617
Messages
4
Reaction score
0

Homework Statement



A ball is tossed so that it bounces off the ground, rises to a height of 3.10 m, and then hits the ground again 0.70 m away from the first bounce.

Homework Equations


H= .5(v^2/g) for y velocity.


The Attempt at a Solution


Vy=squareroot of(60.822) Vy= 7.799 m/s
Vx= .70 m/1.59 s= .441 m/s
inversetangent(Vy+Vx)= angle ------ is this correct?

i did the inversetangent and it came out to be about 79.4 degrees. but that wasn't the correct answer :(
 
Physics news on Phys.org
your Vx , Vy are correct but the angle is wrong.

\tan(\theta)=\frac{V_y}{V_x}=\frac{7.79}{0.44}
 
thank you! :)
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Projectile Motion velocity vector Problem
Replies
2
Views
2K
Uniform Circular Motion and Projectile Motion Help
Replies
14
Views
2K
Projectile Motion Problem: Maximum Height of a Ball Shot into the Air
Replies
11
Views
2K
Oblique soccer shot calculation task
Replies
38
Views
4K
Average force and angle, collision problem
Replies
23
Views
3K
What Is the Angle Between Velocity Vector and Trajectory at Maximum Height?
Replies
1
Views
2K
Projectile motion cannon ball angle
Replies
4
Views
2K
How do I know when velocity is negative in a 1-D motion problem?
Replies
2
Views
1K
How Does Projectile Motion Affect Speed and Angle on Impact?
Replies
2
Views
2K
Throwing a Ball and determining possible angles.
Replies
12
Views
2K

Hot Threads

Recent Insights

Back
Top