What am I doing wrong in finding the derivative and max/min?

[randy17]

Homework Statement

I need to find the max/min of y=(1)/(3+x^2)

Homework Equations

y=(1)/(3+x^2)

The Attempt at a Solution

I tried to find the derivative; y'= (3+x)^-2(1) = -2(3+x)^-3 = -2/(3+x)^3 or -2/3(3+x)^2?

Whats wrong with it?

 

[SteamKing]

Well, for starters, the derivative you calculated is wrong. What derivative rule are you using? Your attempt suggests some confusion.

 

[YawningDog27]

Start off by using the chain rule (or quotient rule, whichever you prefer) to find the derivative of the function.