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Homework Help: What am I doing wrong in finding the derivative and max/min?

  1. Jun 3, 2013 #1
    1. The problem statement, all variables and given/known data

    I need to find the max/min of y=(1)/(3+x^2)

    2. Relevant equations

    y=(1)/(3+x^2)

    3. The attempt at a solution

    I tried to find the derivative; y'= (3+x)^-2(1) = -2(3+x)^-3 = -2/(3+x)^3 or -2/3(3+x)^2?

    Whats wrong with it?
     
  2. jcsd
  3. Jun 4, 2013 #2

    SteamKing

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    Staff Emeritus
    Science Advisor
    Homework Helper

    Well, for starters, the derivative you calculated is wrong. What derivative rule are you using? Your attempt suggests some confusion.
     
  4. Jun 5, 2013 #3
    Start off by using the chain rule (or quotient rule, whichever you prefer) to find the derivative of the function.
     
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