What am I doing wrong in finding the derivative and max/min?

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SUMMARY

The discussion centers on finding the maximum and minimum values of the function y=(1)/(3+x^2). The user incorrectly calculated the derivative as y' = -2/(3+x)^3, indicating confusion with derivative rules. The correct approach involves applying either the chain rule or the quotient rule to derive the function accurately. This foundational understanding is crucial for correctly identifying critical points for optimization.

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Homework Statement



I need to find the max/min of y=(1)/(3+x^2)

Homework Equations



y=(1)/(3+x^2)

The Attempt at a Solution



I tried to find the derivative; y'= (3+x)^-2(1) = -2(3+x)^-3 = -2/(3+x)^3 or -2/3(3+x)^2?

Whats wrong with it?
 
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Well, for starters, the derivative you calculated is wrong. What derivative rule are you using? Your attempt suggests some confusion.
 
Start off by using the chain rule (or quotient rule, whichever you prefer) to find the derivative of the function.
 

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