- #1
JohanL
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Im trying to solve the heat equation in 2dim on a plate.
0=<x=<L, 0=<y=<L. With homogenous dirichlet conditions on the boundary and the initial condition:
T(x,y)=T0sin(pi*x/L)sin(pi*y/L)
With separation of variables i get the solution
[tex]
T(x,y,t)=\sum_{m=0}^\infty\sum_{n=0}^\infty B_{mn}*exp[\frac{-(m^2+n^2)\pi^2kt}{L^2}]*sin[\frac{m\pi x}{L}]*sin[\frac{m\pi y}{L}]
[/tex]
m,n integers and k the constant from the heat equation.
Now the initial condition determine the constants B_mn
[tex]
B_{mn} = \frac{4T_0}{L^2}*\int_{0}^{L}\int_{0}^{L} sin[\frac{\pi x}{L}]*sin[\frac{\pi y}{L}] sin[\frac{m\pi x}{L}]*sin[\frac{n\pi y}{L}] dx dy
[/tex]
But an integral like
[tex]
\int_{0}^{L}sin\frac{\pi x}{L}sin\frac{m\pi x}{L}dx
[/tex]
is zero for m not equal to 1.
So m=1 and n=1...?
and with this i don't get a Fourier series as the solution...
What am i doing wrong ?
0=<x=<L, 0=<y=<L. With homogenous dirichlet conditions on the boundary and the initial condition:
T(x,y)=T0sin(pi*x/L)sin(pi*y/L)
With separation of variables i get the solution
[tex]
T(x,y,t)=\sum_{m=0}^\infty\sum_{n=0}^\infty B_{mn}*exp[\frac{-(m^2+n^2)\pi^2kt}{L^2}]*sin[\frac{m\pi x}{L}]*sin[\frac{m\pi y}{L}]
[/tex]
m,n integers and k the constant from the heat equation.
Now the initial condition determine the constants B_mn
[tex]
B_{mn} = \frac{4T_0}{L^2}*\int_{0}^{L}\int_{0}^{L} sin[\frac{\pi x}{L}]*sin[\frac{\pi y}{L}] sin[\frac{m\pi x}{L}]*sin[\frac{n\pi y}{L}] dx dy
[/tex]
But an integral like
[tex]
\int_{0}^{L}sin\frac{\pi x}{L}sin\frac{m\pi x}{L}dx
[/tex]
is zero for m not equal to 1.
So m=1 and n=1...?
and with this i don't get a Fourier series as the solution...
What am i doing wrong ?
Last edited: