What Angle Does the Polarizing Sheet's Axis Make with the Horizontal Direction?

AI Thread Summary
The discussion centers on determining the angle of a polarizing sheet's transmission axis when 15 percent of horizontally polarized light is transmitted. To find the angle, the relevant formula involves the intensity of transmitted light relative to the incident light. Participants express uncertainty about calculating the initial intensity of the light, suggesting that multiplying the incident intensity by 0.15 is necessary but lacking clarity on the initial value. The conversation highlights the need for understanding the relationship between intensity and angle in polarization. Ultimately, the focus remains on applying the correct formula to ascertain the angle of the polarizing sheet.
Kathi201
Messages
40
Reaction score
0
Light known to be polarized in the horizontal direction is incident on a polarizing sheet. It is observed that only 15 percent of the intensity of the incident light is transmitted through the sheet. What angle does the transmission axis of the sheet make with the horizontal?

I am not quite sure how to figure out what the intensity of the light is. I know that I multiply that by .15 but I do not know how to figure out the value.
 
Physics news on Phys.org
See the formula for transmission I gave in the other post.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top