Elwin.Martin
- 202
- 0
Homework Statement
"A large block of mass m1 executes horizontal SHM as it slides across a friction-less surface under the action of a spring with spring constant k. A block of mass m2 rests upon m1. The coefficient of friction between the two blocks is \mu. Assume that m2 does not slip relative to m1.
(c) what is the angular frequency of oscillations \omega ?
(d) What is the maximum amplitude, A, that the system can have if m2 does not slip relative to m1? (express in terms of \omega
Homework Equations
F=-kx Hooke's Law
\omega = \sqrt{\frac{k}{m}}
The Attempt at a Solution
I'm reviewing for a transfer exam and I'm going through their old finals problems. This came up and I'm hoping I'm not seriously oversimplifying here.
c. \omega = \sqrt{\frac{k}{m_1+m_2}}
d. k(A)= \mu N where N is the normal force from the contact of the blocks
kA= \mu m_2 g
A= \frac{\mu m_2 g}{k}
A= \frac{\mu m_2 g}{k}
From \omega = \sqrt{\frac{k}{m_1+m_2}} , \frac{m_2}{k} = \frac{m_2}{\left(m_1+m_2\right)\omega^2}
A= \frac{\mu m_2 g}{\left(m_1+m_2\right)\omega^2}
...This comes across as odd to me, if I had a normal force which result from both masses, I'd be considerably happier. I see no reason to express the answer in terms of \omega when it comes out kind of ugly. The only explanation I have is that there is some contribution to the normal force I'm neglecting or I made some careless mistake elsewhere.
Any and all help would be great! Just trying to re-learn basic mechanics ><
Edited to add an m_2 where it needed to be.
Last edited: