What Are the Final Speeds of a Material Point and a Wedge Without Friction?

AI Thread Summary
The discussion focuses on calculating the final speeds of a material point and a wedge without friction, using conservation of energy and momentum principles. The equations derived include kinetic energy and momentum conservation, leading to a final speed expression for the material point. The user also addresses a related problem involving an initial speed for the material point to reach maximum height, applying similar conservation laws. The conclusion suggests that the approach taken is correct, particularly in equating the speeds of the two bodies at maximum height. The overall analysis emphasizes the application of fundamental physics principles in solving the problem.
Karozo
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Homework Statement



I think that the image is clear.
There isn't friction, not the material point with wedge, not the wedge with the floor.

At time t=0 the material point start to move, I need to find the final speed of the two objects at time t\rightarrow\infty.

Homework Equations



I have used conservation of energy and momentum.

The Attempt at a Solution



So I have two equation:
\frac{1}{2}m{v_m}^2+\frac{1}{2}M{v_M}^2 = mgR

m{v_m}+M{v_M}=0

And the solution is {v_m}=\sqrt{\frac{mgR}{\frac{1}{2}m+\frac{1}{2}\frac{m^2}{M}}}

Am I wrong?
 

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It can be simplified, but it looks okay. What about the velocity of the other object?
 
Well, if V_m is right is very simple to find V_M, so I haven't written it.
 
I have also a similar problem, you can see the image.

In this the mass m, start with an initial speed v_0, you have to find v_0 so that the material point has maximum height R.

I think that is right to use the two equations:

\frac{1}{2}m{v_m}^2+\frac{1}{2}M{v_M}^2+mgR=\frac{1}{2}m{v_0}^2 energy

m{v_m}+M{v_M}=mv_0 momentum

for the point of maximum height, and then you have {v_m}={v_M} , because the two bodies are in contact.
 

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Karozo said:
I have also a similar problem, you can see the image.
Next time, you should put a new problem in a new thread.

In this the mass m, start with an initial speed v_0, you have to find v_0 so that the material point has maximum height R.

I think that is right to use the two equations:

\frac{1}{2}m{v_m}^2+\frac{1}{2}M{v_M}^2+mgR=\frac{1}{2}m{v_0}^2 energy

m{v_m}+M{v_M}=mv_0 momentum

for the point of maximum height, and then you have {v_m}={v_M} , because the two bodies are in contact.
That appears correct.
 
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