What Are the Limits of m1 to Prevent System Acceleration with µ=0.42?

  • Thread starter Thread starter meganw
  • Start date Start date
  • Tags Tags
    Forces Friction
AI Thread Summary
The discussion focuses on determining the minimum and maximum values of mass m1 to prevent system acceleration, given a coefficient of friction (µ) of 0.42. The equations of motion and forces, including friction and gravity, are applied to analyze the system. An attempt to solve for m1 resulted in an incorrect value due to missing components in the force analysis. The importance of considering the net force along the diagonal direction is emphasized for accurate calculations. Correctly accounting for all forces is crucial to finding the right mass range for m1.
meganw
Messages
96
Reaction score
0

Homework Statement



What are the minimum and maximum values of m1 in the figure to keep the system from accelerating? Take µs = µk = 0.42.

5-30.gif


________ kg < (or equal to) m1 < (or equal to) ________ kg


Homework Equations



F = m(a)
Ff=Mk(N)
Ff=Ms(n)

The Attempt at a Solution



Fy(net)=0=Fn-Fgy
Fgy=Fgcos30
Fg=9.8m
Fn=9.8mcos30

Ff=.42(9.8mcos30)

Does Ff equal 49 since Fg of mass 2=49 and thus Ft must equal 49 so mass 2 doesn't move and then that means the Ft on the mass 1 also equals 49 so Ff must also equal 49??

49=.42(9.8mcos30)

I get m=13.75 which is wrong. :(
 
Physics news on Phys.org
You didn't write the net force along the diagonal direction. If you did, you'd notice that something was missing.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top