What Are the Steps for Using Change of Variables to Find Bounded Regions?

mattbonner
Messages
14
Reaction score
0

Homework Statement


using change of variables, find the region bounded by
y = x, y = 2x, xy = 1, xy=2


Homework Equations





The Attempt at a Solution


i know i have to introduce the variables u, v
the problem is i don't understand how to introduce them
i tried read the textbook but the examples all introduce the new variables for you

i think i understand the steps that follow, I am just stuck at the beginning
 
Physics news on Phys.org
Well, you would like your uv integral to have constant limits if possible. You have xy=1 and xy=2 so that certainly suggests setting u or v = xy. If you use v, then v will go from 1 to 2.

Now can you see how to choose u so that y = x and y = 2x give you constant limits for u?
 
i guess y/x?
that'll give me 1 to 2 as well?
 
Good guess. I hope it wasn't a pure guess. You don't have to ask about the limits. Look at the equations. And plot your uv region.
 
i vaguely remembered a similar example the prof did, i missed how he had chosen u and v, which resulted in my confusion

thank you so much for the help!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top