What Are the True Statements About Tension in a Simple Pendulum?

AI Thread Summary
The discussion focuses on the tension in a simple pendulum, with participants evaluating true or false statements regarding the relationship between tension (T), mass (M), and gravitational force (mg). It is clarified that T is not greater than mg when the pendulum is at its maximum amplitude (q0) and that T equals mg only when the pendulum is vertical (theta = 0). The vertical component of tension is constant, aligning with the force of gravity. Participants emphasize the importance of using Newton's second law to analyze the forces involved. Overall, the conversation highlights the need for accurate application of physics principles in understanding pendulum dynamics.
lmlgrey
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Simple pendulum question.. help needed!

http://capa.mcgill.ca/res/mcgill/dcmcgill/oldproblems/msuphysislib/Graphics/Gtype26/prob34a_pendSHM1.gif1.[/URL] The diagram shows a simple pendulum consisting of a mass M suspended by a thin string. The magnitude of the tension is T. The mass swings back and forth between ±q0 Choose True or False

True False T is greater than Mg for q = q0.
True False T equals Mg when q = q0.
True False T=Mg at some angle between zero and q0.
True False The vertical component of tension is constant.









2. is it true that T = mg*cos(theta) always?



The vertical component of tension is constant ... true, since the vertical component=force of gravity
T is greater than mg when q=q0. ... false, since q0 is the apex, and T is the smallest when the ampliude is the greatest

I don't know about the other two...especially: T=Mg at some angle between zero and q0
my guess at that question is that since T= Mgcos(theta), therefore, T will only equal to mg when theta=0 or 180? so it would be false?




 
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lmlgrey said:
The diagram shows a simple pendulum consisting of a mass M suspended by a thin string. The magnitude of the tension is T. The mass swings back and forth between ±q0

Hi lmlgrey! :smile:

Don't guess! :frown:

Physics is equations, so always find the right equation, and follow it through.

In this case, the right equation is Newton's second law, F = ma.

Most of your answer is wrong, because you've ignored the ma part.

Try again! :smile:
 
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