What are the two possible values of K given a specific distance from a point?

  • Thread starter Thread starter Mo
  • Start date Start date
AI Thread Summary
The discussion revolves around finding the two possible values of K for the point (3, k), which is 5 units away from the point (0, 1). The key concept is to use the distance formula, setting the distance between the two points equal to 5, leading to the equation √((3-0)² + (k-1)²) = 5. Squaring both sides simplifies the problem to a quadratic equation, which yields two solutions for K. The geometric interpretation involves a circle centered at (0, 1) with a radius of 5, intersecting the vertical line x = 3 at two points. The final values obtained for K are -3 and 5.
Mo
Messages
81
Reaction score
0
I have managaed to do all of the questions upto this one without getting an answer wrong .. but this question .. i just don't quite understand it.

"The point (3 , k) is a distance of 5 units from (0, 1) .

Find the two possible values of K"

What exactly do they mean by "5 units"

I am thinking that i am going to need to compare the length (3,k) to (0 ,1) plus "5 units" .And then solve for K :confused:

I don't need an answer, i need the question (push in the right direction would be nice) :smile:

Regards,
Mo

PS: Also .. rather unrelated .. what exactly is K-12 ... because I am in college in UK .. but I am 16 (usual age when people enter college in UK) should my question be posted here in k-12 .. or "Homework:College level"?
 
Last edited:
Physics news on Phys.org
To answer you last question first: In the United States, children normally start in "kindergarten" (A German word!) at age five and then continue through 12 years (1st grade to 12th) so that they are typically 18 years old when they go to college.


Now, for your mathematical question.

"The point (3 , k) is a distance of 5 units from (0, 1) .

Find the two possible values of K"

What exactly do they mean by "5 units"

What do they mean by (0,1) or (3,k)? The point (0,1) is on the y-axis exactly 1 "unit" above the x axis. The point (3,k) is three "units" to the right of the y-axis and k "units" from the x-axis. A "unit" is whatever units (mm, meter, inch, mile or made up unit) are used to mark the axes.

'I am thinking that i am going to need to compare the length (3,k) to (0 ,1) plus "5 units" '

No, (3,k) is a point- it does not have a length! The line segment from (3,k) to (0,1) has a length: \sqrt{(3-0)^2+ (k-1)^2}. Set THAT equal to 5 and solve for k. (hint: first thing you should do is square both sides). That will give you a quadratic equation which has two solutions.

You could do this geometrically: the set of all points which have distance 5 from (0,1) is the circle with radius 5 and center (0,1). That circle will cross the line x= 3 in two places. k is the y coordinate of those two places.
 
Thanks for your help, most appreciated.I got the answer in the end (k=-3, k=5) which is correct according to the answers.I guess its better for me to post in here! thanks again.

Regrads,
Mo
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top