What Determines the Electric Field Magnitude at Half the Radius of a Solenoid?

AI Thread Summary
The discussion centers on determining the electric field magnitude at a distance of R/2 from the axis of a long solenoid with changing current. The relevant equation for the magnetic field is μ0(N/L)I, but confusion arises when applying this to find the electric field at R/2. The correct expression for the electric field includes a factor of R/4, which is not immediately clear to the participants. Clarification is sought regarding the interpretation of R in the context of the problem. Understanding the derivation of the factor in the denominator is essential for solving the problem accurately.
freddy13
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Homework Statement



A long solenoid of radius R, length L (which
is much longer than R), number of windings
N, has a current I that is changing in time at
a rate (dI/dt). What is the magnitude of the
electric eld a distance R=2 from the axis of
the solenoid?

Homework Equations



μ0(N/L)I

The Attempt at a Solution



I thought I had this completely right until I get to the R/2 Part. if you just throw the R/2 part into the equation, then you get the B field I believe, but the answer is: μ0(dI/dt)(N/L)R/4.

I am not seeing where the 4 in the denominator comes from unless we had some kind of divisible action of R going on somewhere, or something. Not really sure how to proceed!
 
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freddy13 said:

Homework Statement



What is the magnitude of the
electric eld a distance R=2 from the axis of
the solenoid?

!

Start by stating the problem correctly. What do you mean by "R=2"? Did you mean R/2? 2R?
 
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