- #1
th77
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Only two horizontal forces act on a 3.0 kg body. One force is 9.0N, acting due east, and the othr is 8N, acting 62 degrees north of west. What is the magnitude of the body's acceleration?
Fnet= ma ...so I took that to mean F1x + F2x = ma
F1x = 9 cos 0 = 9
f2x = 8 cos 62 = 3.76
a = (9 + 3.76)/3 = 4.25
The solution says 2.9
Fnet= ma ...so I took that to mean F1x + F2x = ma
F1x = 9 cos 0 = 9
f2x = 8 cos 62 = 3.76
a = (9 + 3.76)/3 = 4.25
The solution says 2.9