What Does a ≡ b (mod m) Imply in Mathematics?

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The expression a ≡ b (mod m) indicates that the difference between a and b is divisible by m, meaning they have the same remainder when divided by m. In the context of integers, this can be expressed as (a - b) being a multiple of m. The discussion also touches on solving the equation (2/3) = x (mod 5), which leads to the equivalent equation 2 - 3x ≡ 0 (mod 5). The solution x = 4 is confirmed to be correct, as it satisfies the modular condition. Understanding these concepts is crucial for working with modular arithmetic effectively.
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What exactly does this mean?
a=b (mod m)
My teacher didn't attempt explain this but I'd still like to know.
 
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a \equiv b \mod m, means a is a multiple of m plus b. (a,b and m are integers)

It means when you divide a by b, you get a rest of m.

In algebra, a,b and m are not necessarily integers, but in most cases they are.
 
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So how do you solve (2/3)= x (mod 5) for x?
I'm told that x=4, but if m<|b|, then that can't be right.
 
What exactly does this mean?
a=b (mod m)
For integers "a", "b", and "m" (m > 0),
a = b (mod m)
if and only if (a - b) is exactly divisible by "m" (or equivalently, that "a" divided by "m" has the same remainder as "b" divided by "m").

Example:
10 = 4 (mod 3)
---> (10 - 4)/3 = Integer
---> {10 divided by 3} has same remainder as {4 divided by 3}


~~
 
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yay_goobers2112 said:
So how do you solve (2/3)= x (mod 5) for x?
I'm told that x=4, but if m<|b|, then that can't be right.
I'm sorry, that remark was wrong. Just use the second one: :biggrin:

a \equiv b \mod m means division of a by b will give rest m.

I'ven't seen fractions on the left side of congruences before, but they probably mean (multiplying both sides by 3):

2 = 3x \mod 5

or

2-3x = 0 \mod 5
So 2-3x must be a multiple of 5, so x =4 will work.
 
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