What Does the Equation (KE1-KE2)/KE2 = M/(M+m) Represent in Physics?

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The equation (KE1-KE2)/KE2 = M/(M+m) relates to the conservation of energy and momentum during collisions, specifically addressing the theoretical fractional energy loss in inelastic collisions. The variables M and m represent the masses of two colliding objects within a system, where KE_i is the initial kinetic energy and KE_f is the final kinetic energy. The discussion emphasizes that when velocities are much less than the speed of light, kinetic energy can be calculated using the classical formula KE = 1/2 mv^2, while relativistic effects must be considered at higher speeds. The inquiry seeks clarification on the equation's derivation and its applications, particularly in mechanics rather than molecular kinetic theory. Understanding this equation is crucial for analyzing energy transformations in collision scenarios.
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hi i have a question. What does this equation mean??
(KE1-KE2)/KE2=M/(M+m) and how is it derived??

I don't understand. Please help me.
 
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Could you give more information? For instance does this have anything to do with planets, pendulums, levers, or pullies?
 
What does M and m represent? Is this molecular kinetic theory? (i.e. M is mass of volume V of gas and m is the mass of one molecule) or is it mechanics?
 
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heyy...sorry

the question has to do with collision..the conservation of energy and momentum. the formula has to do with the theoretical fractional energy loss
the letters "f" and "i" are subscript. (KEi-KEf)/KEi=M(M+m)
The M and m are masses. I don't know how to give anymore information because that's about all i know. please help.. anyone who understands these things...
 
It looks like you have two objects in a system and this systme has an initial kinetic energy of KE_i and a final kinetic energy of KE_f. When v<<c, KE= \frac{1}{2}mv^2. When v is not v<<c then KE= \frac{mc^2}{\sqrt{1-v^2/c^2}}-mc^2.

Some of the kinetic energy will be lost if the collision is inelastic.
 
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