What electric field strength will cause the bead to hang suspended in the air?

AI Thread Summary
To determine the electric field strength required to suspend a 0.180g plastic bead charged with 0.700 x 10^10 excess electrons, the equation F=qE is used, where F equals the gravitational force (mg). The charge q can be calculated by multiplying the number of excess electrons by the charge of a single electron. The relationship qE = mg indicates that the electric force must equal the weight of the bead for it to hang suspended. The discussion highlights confusion regarding the calculations and the need for clarity on formulas presented in lectures. Understanding these principles is essential for solving the problem effectively.
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1. A 0.180g plastic bead is charged by the addition of 0.700 x 10^10 excess electrons. What electric field strength will cause the bead to hang suspended in the air?



2. Is amount of excess electrons the exact same as the charge of the bead??



3. I am sure you use F=qE. But I am pretty stuck at the rest of it. I am sure there is a formula or soemthing i missed in lecture considering my prof is a little loopy.
 
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Set qE = mg. q is the charge of 0.7 * 10^10 electrons, m is the mass of the bead, g is acceleration due to gravity. Shouldn't be too hard.
 
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