What equation should I use to find the normal of a triangle?

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Homework Statement



The triangle obtained by tracing out the path from (6, 0, 0) to (6, 0, 2) to (6, 5, 2) to (6, 0, 0)

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The Attempt at a Solution



Should I use the following equation Ax + By + Cz = d and find the normal first?
 
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What is the question? You title this "equation of the triangle" but a triangle doesn't have an "equation". Do you mean to integrate some function over the region bounded by the triangle?
 
yes that's what I actually meant
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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