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What fraction of the sign's weight is supported by each string?

  1. Apr 1, 2003 #1
    I am stuck on one of the AP Physics problems. Could you please help me out and give some pointers on how to solve the following problem:

    A hemispherical sign 1 m in diameter and of uniform mass density is supported by two strings. What fraction of the sign's weight is supported by each string?

    [see attachment for the diagram]

    Thank you
     

    Attached Files:

    Last edited by a moderator: Apr 2, 2003
  2. jcsd
  3. Apr 1, 2003 #2

    russ_watters

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    [searches in vain for an attachment...]
     
  4. Apr 2, 2003 #3

    HallsofIvy

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    I was able to down load the attachement without any trouble.

    I shows a semicircle with two lines (the supporting cables) going up from (first cable) one end of a diameter and (2nd cable) 0.75 meters along (I assume) the diameter and so 0.25 meters from the other end.

    Let W be the weight of the sign, F1 and F2 be the forces on the respective cables. Obviously F1+F2= W. The total torque must be 0 (about any point- in particular about the point of attachment of cable 1) so -W(1/2 meter) (the torque due to the weight of the sign)plus F_2(0.75) must be 0.
    (0.75)F_2- 0.5 W= 0 or F_2= (0.5/0.75)W= (2/3)W.

    From F_1+ F_2= W we get F_1+ (2/3)W= W or F_1= (1/3)W.

    The cable at the back is supporting 1/3 of the weight and the one in front is supporting 2/3 of the weight.
     
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