What Happens to Forces and Motion When Variables Change?

AI Thread Summary
When the mass of a cart is halved, it covers a greater distance when pushed due to the relationship between force and acceleration. Pushing for twice the duration results in a final speed that is also doubled, as acceleration remains constant. If the pushing time is doubled, the distance covered increases by a factor of four, since distance is proportional to the square of time under constant acceleration. Doubling the force applied leads to a final speed that is also doubled, confirming the direct relationship between force and acceleration. Understanding these principles is crucial for solving problems related to forces and motion.
needhelpfast
Messages
20
Reaction score
0

Homework Statement



Leaving all other quantities unchanged, what happens in the scenarios below?
• If you use a cart with half the mass, you cover distance during pushing.
• If you push twice as long, you reach final speed.
• If you push twice as long, you cover distance during pushing.
• If you double the force, you reach final speed.

Homework Equations



i think f=ma

The Attempt at a Solution



I thought the answers were double, double, half, double, but these are wrong. Any help is greatly appreciated!
 
Physics news on Phys.org
This is sort of confusing...

I would use s=0.5at^2

and v=a*t

based on this

1) double, because a=2F/m

2) twice as long distance or time?

if time double

3) 4x, because t is in the power of 2

4) you should be able to figure this one out now.
 
Thanks for your help!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top