What Happens to the Remaining Support When One Is Removed From a Supported Rod?

AI Thread Summary
When one support of a uniform thin rod is removed, the force on the remaining support must counterbalance the weight of the rod. The equation F1 + F2 = mg indicates that the total vertical forces must equal the weight of the rod, which is 100 N. Upon removing one support, the remaining support must immediately bear the entire weight, resulting in a force of 100 N. The situation becomes unstable as the rod is no longer stationary. Understanding the dynamics of the system is crucial for accurate analysis.
EndoBendo
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Homework Statement



A uniform thin rod of weight W = 100 N is supported horizontally by two vertical
props at its ends. At time t = 0 one of the these supports is kicked out. Find the
force on the other support immediately thereafter.

Homework Equations



F1 + F2 = mg


The Attempt at a Solution



-F1(L) + 100N(L) = 0
100N = F1

seems too simple.. i don't understand what i did, i just plugged it into a formula i found in the book...
 
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EndoBendo said:

Homework Statement



A uniform thin rod of weight W = 100 N is supported horizontally by two vertical
props at its ends. At time t = 0 one of the these supports is kicked out. Find the
force on the other support immediately thereafter.

Homework Equations



F1 + F2 = mg


The Attempt at a Solution



-F1(L) + 100N(L) = 0
100N = F1

seems too simple.. i don't understand what i did, i just plugged it into a formula i found in the book...

Once one support is kicked out it is no longer a stable/stationary rod.
 

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