What Happens When Force is Not Constant in W = f x D?

  • Thread starter Thread starter thomero
  • Start date Start date
  • Tags Tags
    Constant Force
AI Thread Summary
When the applied force is not constant, the equation W = f x D, which calculates work, becomes invalid. This equation only applies when both force and distance are constant and measured in the same direction. To analyze variable forces, a more general approach involving calculus and vectors is necessary. By considering small increments of distance and summing the contributions of force over the total distance, one can calculate work done under varying forces. Understanding these concepts is essential for accurately determining work in dynamic systems.
thomero
Messages
4
Reaction score
0

Homework Statement


W = f x D
W = work
f = force
D = distance

What happens when the applied force is not constant?


I have no idea. Can anyone please answer?
Thank you.
 
Physics news on Phys.org
Do you know how the force varies with time? Is there a function that expresses this?
 
No. Its just a research question that just ask what happens when the applied force is not constant.
 
W = F*D is only valid for a constant force and distance measured in the direction in which the force acts. There is a more general equation relating a variable force to distance and work. Properly, it involves calculus and vectors. Not sure what level you're at.
Ignoring the vector aspect, consider the force advancing a small distance ds, so that the force can be taken as not varying enough to matter. Then add up all these contributions over the total distance moved.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top