What is the acceleration of a 7.00 kg sphere in seawater at a depth of 1.20 km?

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To determine the acceleration of a 7.00 kg sphere in seawater at a depth of 1.20 km, first calculate the weight of the sphere using the formula weight (mg). Next, find the buoyant force by calculating the volume of the sphere and multiplying it by the density of seawater (1025 kg/m^3). The net force acting on the sphere is the difference between the buoyant force and the weight, which allows for the calculation of acceleration using Newton's second law (F=ma). The direction of the acceleration will be upwards if the buoyant force exceeds the weight. This approach provides a clear method to find the sphere's acceleration and direction.
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A 7.00 kg sphere of radius 5.00 cm is at depth of 1.20 km in seawater that has density 1025 kg/m^3.What is the magnitude and direction of the spheres accelreation if its free to move?
i got to the part were i don't know what the mass of the sphere is help anyone please i tried f=ma no work
 
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Um, isn't the mass of the sphere given, 7.00kg?
 
yes u are right thanks
 
Wasn't sure if you'd figured out your peoblem yet or not, but here goes...

Find your weight (mg) and bouyancy forces (related to the volume of sea water displaced (ie volume of sphere using radius)) and you should be able to get acceleration and direction from your resultant force.
 
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