What is the acceleration of a block being pulled up a slope by a 140 N force?

AI Thread Summary
To calculate the acceleration of a 10.0 kg block being pulled up a 35-degree slope by a 140 N force with a coefficient of friction of 0.100, one must first create a free-body diagram to visualize the forces involved. The forces include the applied force of 140 N, the normal force, gravitational force, and frictional force. The coefficient of friction is essential for determining the frictional force, which opposes the motion. The net force acting on the block can be calculated by subtracting the frictional force from the applied force, and then applying Newton's second law to find the acceleration. Understanding these components is crucial for solving the problem accurately.
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Homework Statement


Calculate the acceleration for a 10.0kg block which is being pulled up a 35 degree slope by a force of 140 N if the coefficient of friction is 0.100 The answer is to be in m/s2


Homework Equations


Ff=UN



The Attempt at a Solution



I am having trouble getting started and putting the parts of the problem together.
 
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Start with a picture and free-body diagram.

ehild
 
I have a free body which a 140 N force going along the + x-axis a N force (normal) going + along Y axis a vector "W" in the third quad with a polar angle of 235'. What do i do next. I know that i need to find the acceleration of the block. Where and how does the coeficient of friction come into play here?
 
I still need that picture with all forces shown. There is gravity and friction in addition to that 140 N force. The resultant force accelerates the block.

ehild
 
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