What is the acceleration of a crate after it has just started to move?

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The discussion focuses on calculating the acceleration of a crate after it begins to move, given the coefficients of static and kinetic friction. The static friction force is determined using the static friction coefficient and the normal force, while the kinetic friction force is calculated with the kinetic friction coefficient. The net force acting on the crate once it starts moving is the difference between the static force and the kinetic friction force. The incorrect initial acceleration calculation of 4.39 m/s² indicates a misunderstanding in applying the forces. Properly accounting for these forces will yield the correct acceleration of the crate.
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Homework Statement



The coefficients of static and kinetic friction between a 445 N crate and the warehouse floor are 0.565 and 0.450, respectively. A worker gradually increases his horizontal push against this crate until it just begins to move and from then on maintains that same maximum push.


Homework Equations


What is the acceleration of a crate after it has just started to move?


The Attempt at a Solution



I tried to multiply the kinectic friction coefficient by the Normal Force to get kinetic friction. Then I tried to divide Kinectic Friction by the mass of the box and I got:

4.39 m/s2 but it was wrong.
 
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quanitary said:

Homework Statement



The coefficients of static and kinetic friction between a 445 N crate and the warehouse floor are 0.565 and 0.450, respectively. A worker gradually increases his horizontal push against this crate until it just begins to move and from then on maintains that same maximum push.


Homework Equations


What is the acceleration of a crate after it has just started to move?


The Attempt at a Solution



I tried to multiply the kinectic friction coefficient by the Normal Force to get kinetic friction. Then I tried to divide Kinectic Friction by the mass of the box and I got:

4.39 m/s2 but it was wrong.

The force needed to start moving the box is F_static= mu_static * Normal
Once the box starts moving the force of kinetic friction is F_kinetic=mu_kinetic *normal

The net force at that point is F_net=F_static-F-kinetic
a = F_net/mass_crate
 
korican04 said:
The force needed to start moving the box is F_static= mu_static * Normal
Once the box starts moving the force of kinetic friction is F_kinetic=mu_kinetic *normal

The net force at that point is F_net=F_static-F-kinetic
a = F_net/mass_crate

Thanks!
 
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