What is the acceleration of a crate after it has just started to move?

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SUMMARY

The acceleration of a crate after it has just started to move can be calculated using the coefficients of static and kinetic friction. For a 445 N crate with a static friction coefficient of 0.565 and a kinetic friction coefficient of 0.450, the force required to initiate movement is determined by F_static = μ_static * Normal Force. Once in motion, the kinetic friction force is F_kinetic = μ_kinetic * Normal Force. The net force is then calculated as F_net = F_static - F_kinetic, leading to the acceleration formula a = F_net/mass_crate.

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Homework Statement



The coefficients of static and kinetic friction between a 445 N crate and the warehouse floor are 0.565 and 0.450, respectively. A worker gradually increases his horizontal push against this crate until it just begins to move and from then on maintains that same maximum push.


Homework Equations


What is the acceleration of a crate after it has just started to move?


The Attempt at a Solution



I tried to multiply the kinectic friction coefficient by the Normal Force to get kinetic friction. Then I tried to divide Kinectic Friction by the mass of the box and I got:

4.39 m/s2 but it was wrong.
 
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quanitary said:

Homework Statement



The coefficients of static and kinetic friction between a 445 N crate and the warehouse floor are 0.565 and 0.450, respectively. A worker gradually increases his horizontal push against this crate until it just begins to move and from then on maintains that same maximum push.


Homework Equations


What is the acceleration of a crate after it has just started to move?


The Attempt at a Solution



I tried to multiply the kinectic friction coefficient by the Normal Force to get kinetic friction. Then I tried to divide Kinectic Friction by the mass of the box and I got:

4.39 m/s2 but it was wrong.

The force needed to start moving the box is F_static= mu_static * Normal
Once the box starts moving the force of kinetic friction is F_kinetic=mu_kinetic *normal

The net force at that point is F_net=F_static-F-kinetic
a = F_net/mass_crate
 
korican04 said:
The force needed to start moving the box is F_static= mu_static * Normal
Once the box starts moving the force of kinetic friction is F_kinetic=mu_kinetic *normal

The net force at that point is F_net=F_static-F-kinetic
a = F_net/mass_crate

Thanks!
 

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