What is the Acceleration of a Small Body Moving on a Parabola?

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A small body moving along the parabola y=ax^2 with constant velocity requires determining its acceleration at x=0. The discussion highlights that while the speed is constant, the direction of the velocity vector changes, indicating that there is acceleration present. The acceleration is orthogonal to the velocity due to the constant speed condition. To find the magnitude of the acceleration, one can differentiate the position equations to derive the components of acceleration. Ultimately, understanding the relationship between velocity and acceleration in this context is crucial for solving the problem.
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Homework Statement



a small body is moving in the plane xy with a constant (in size) velocity [ sorry for my english]. Find the acceleration for x=0 for the parabola y=ax^2

Homework Equations





The Attempt at a Solution



v^2= a_x^2 +a_y^2 \\ \vec{v}= a_x\vec{x}+ a_y*\vec{y} and $$\vec{a}=d\vec{v}/dt$$

I'm kind of lost now, mainly because I'm new to differentiating vectors... Any help would be helpful...
 
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Constant velocity means that acceleration is 0 or that the direction of velocity is changing, so is the velocity changing direction?
 
The magnitude of the velocity is usually called the speed. If the speed is constant then any acceleration is orthogonal to the velocity. So what direction will the acceleration be in at x=0?
It remains to determine the magnitude of the acceleration. By differentiating the equations you have you should be able to determine ##\ddot x^2+ \ddot y^2## as a function of x and the speed.
 
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