What Is the Angle of Inclination for a Car on a Banked Track?

AI Thread Summary
To calculate the angle of inclination for a car on a banked track, the relevant equation is tan(theta) = V²/(rg). Given a car mass of 1000 kg moving at 108 km/h (30 m/s) around a track with a radius of 100 m, the equation simplifies to theta = tan^-1(900/(100g)). Here, g represents the acceleration due to gravity, approximately 9.8 m/s². The final calculation leads to the angle of inclination needed for the car to maintain its path on the banked track.
chrisridgwell
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a car of mass 1000kg moves round a banked track at a constant speed of 108km/h. the reaction of the wheels is at right angles to the track, the horizontal radius is 100m. calculate the angle of inclination of the track.



Homework Equations


tan(theta)= V^2/rg



The Attempt at a Solution


108km/h = 30m/s
(theta)= Tan^-1(900/(100 x g))

im confused as to what g actually stands for
 
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chrisridgwell said:
im confused as to what g actually stands for
g is the acceleration due to gravity; g ≈ 9.8 m/s².
 
so the equation should read:
theta= tan^-1(900/(100x9.8))
 
Yes.
 
Thankyou very much, I am sure i will return
 

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