What is the approximate diameter of the latex balloon after inflation?

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The discussion revolves around calculating the diameter of a latex balloon inflated with 1500 liters of helium for a high-altitude experiment. The volume of the balloon is converted to cubic meters, leading to a calculated radius of approximately 0.710 meters, resulting in a diameter of 1.42 meters. However, the expected correct answer is stated to be 3.1 meters, raising questions about the accuracy of the problem's parameters. Participants consider whether factors like altitude effects or initial helium compression could explain the discrepancy. The conversation highlights the importance of verifying assumptions in physics problems.
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Homework Statement



In a recent high altitude experiment, some physics students used 1500 liter of helium to inflate a latex sounding balloon that would ascend to an altitude of over 30 km. what was the approximate diameter of the (assumed spherical) balloon after inflation?


Homework Equations



volume of a sphere= (4/3)(pi)(r^3)

1 liter = 1.0E-3

The Attempt at a Solution



V=(4/3)(pi)(r^3)

so,

r = [(3V)/(4(pi))]^(1/3)

(1500liter)(1.0E-3m^3/1liter)= 1.5m^3

[((3)(1.5m^3))/((4)(pi))]^(1/3) = .710m

2r = 1.42m

Correct answer should be 3.1 m

Could someone help me out..

Thanks
 
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The supposed correct answer seems out of line for the question posed. Are you sure the problem didn't involve the size of the balloon at 30km altitude? Or that the helium was in some initially compressed condition?
 
No, copied question word for word. Thanks for taking a look at it.
 
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