What is the Average Friction Force Experienced by a Bullet Piercing a Sandbag?

  • Thread starter Thread starter juggalomike
  • Start date Start date
  • Tags Tags
    Average Friction
AI Thread Summary
To find the average friction force experienced by a bullet piercing a sandbag, the problem involves calculating the change in kinetic energy as the bullet slows down. The bullet, weighing 16 g and traveling initially at 51 m/s, emerges from the 13 cm thick sandbag at 14 m/s. The work done by the friction force equals the change in kinetic energy of the bullet. The discussion highlights confusion regarding the appropriate equations, emphasizing the need to focus on energy principles rather than kinematics. Understanding the relationship between work, friction, and kinetic energy is crucial for solving this problem.
juggalomike
Messages
49
Reaction score
0

Homework Statement



A 16 g bullet pierces a sand bag 13cm thick. If the initial bullet velocity was 51m/s and it emerged from the sandbag with 14m/s, what is the average magnitude of the friction force the bullet experienced while it traveled through the bag?

Homework Equations



k+u=k+u?

The Attempt at a Solution


I am completely stumped on this equation, i think my problem is that i keep thinking kinematics but i don't believe that is how we are supposed to solve it as we are currently working on energy
 
Physics news on Phys.org
Work done due to frictional force = change in KE.
 
lol thanks
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top