What is the Braking Force of a Car with No Friction?

AI Thread Summary
To calculate the braking force of a car with no friction, the mass of the car is 1000 kg, and it decelerates from 20 m/s to rest in 5 seconds. The acceleration is determined by dividing the change in velocity (20 m/s) by the time (5 s), resulting in 4 m/s². Using Newton's second law, the force is calculated by multiplying the mass by the acceleration, yielding a braking force of 4000 N. A detailed step-by-step explanation confirms that the correct answer is indeed 4000 N.
XphysicsblurX
Messages
2
Reaction score
0
I need help with my Physics Homework!

A Car of mass 1000kg decelerates from 20m/s2 to rest in a time of 5 seconds. Calculate the braking force of the car, assuming that there is no friction.


Ans:
20 m/s2 / 5 seconds = 4m/s2
Force= ma= 1000 * 4 = 4000N

Can anyone explain this to me?
 
Physics news on Phys.org


Welcome to PF. :)
We're here to help you do your homework, not to do it for you. Please show your attempt at the solution first, or we won't help.

First make sure you got all the relevant data written down right.
Was the initial velocity of the car 20 m/s? (NOT m/s², those are the units of acceleration!)

Data:
Mcar = 1000 kg
Vi = 20 m/s
thalt = 5 s
Vf = 0 (The car breaks to a halt)

What formula do you know linking initial velocity, final velocity, and acceleration?
What formula do you know linking acceleration, mass and force?
 


4ms is acceleration .. the formula is vt=vo-at (if decelerates) after that you can multyplie with car mass 1000 kg (f=m.a)
 


Yes, I know the answer is 4000N, and the solution is there, I got the answer wrong in my test paper, I nned to know why the correct answer is 4000N.

The given solution was:
20 m/s divided by 5 seconds = 4m/s2
Force= ma= 1000 X 4 = 4000N

I need someone to explain step-by-step...
 


Starting with Newton's 2nd Law: F = ma = mass * acceleration. We know the mass obviously. The acceleration, however, for a constant force, is the change in velocity divided by the change in time, that is:

<br /> \frac{{\Delta v}}{{\Delta t}} = \frac{{20m/s}}{{5s}} = 4m/s^2 <br />

Now to find the force, it's simply:

<br /> F = ma = 1000kg*4m/s^2 = 4000N<br />
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top