What is the Circuit for a Diode OR Gate with a 12V Battery Backup?

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The discussion focuses on the electrical circuit for a diode OR gate powered by a 12V battery backup. It explains that the 12V battery activates only when the primary 15V power supply fails, ensuring uninterrupted power. The orientation of diodes in the circuit determines current flow; when the 15V supply is active, one diode is reverse biased, preventing current flow. Upon power failure, the second diode conducts, reversing the bias of the first diode and allowing the battery to take over. The user seeks clarification on circuit design and the inclusion of a resistor to account for Earth resistance, inviting suggestions for improvements.
dobry_den
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Hi! http://www.phys.uAlberta.ca/~gingrich/phys395/notes/node71.html" 's an electrical network for a diode OR gate. It says there that "[t]he 12 V battery does nothing until the power fails; then it takes over without interruption."

I just wonder what electrical circuits (closed loops) are there. I attached an image of how I think the loop looks when the 15V power supply works. But what about the battery loop in this case?
 

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In Loop1 (see the attached images), the orientation of the diode makes it impossible for the current to flow. But in the Loop2, the orientation of the same diode is fine for the current to flow - so what stops it from flowing?
 

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When the 15V supply is on, the 2nd diode is reverse biased (with about 14.3V on its cathode, and 12V on its anode). When the 15V supply is turned off, then the second diode conducts with 12V on its anode and about 11.3V on its cathode. This puts the first diode into reverse bias (off), with 11.3V on its cathode and 0V on its anode. Make sense?
 
Yep, it makes in a way..thanks. But still, I have another question. Could the electric circuit be redrawn in the way I did it in the attached image? The resistor is there to incorporate the resistance of the Earth. Or would you propose any changes?

Any help is appreciated, thanks in advance.
 

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