What is the common velocity of the arrow

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Homework Help Overview

The problem involves a collision between an arrow and an apple, focusing on the conservation of momentum. The arrow has an initial horizontal velocity, and the apple is initially at rest. The goal is to determine the common velocity of both objects after they collide and stick together.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of initial momentum and question the application of momentum conservation principles. There are attempts to set up equations based on the masses and velocities involved, with some participants expressing confusion about the implications of momentum being zero.

Discussion Status

Some participants have offered guidance on rewriting equations to reflect the collision scenario. There is an ongoing exploration of different interpretations of momentum before and after the impact, with no clear consensus reached yet.

Contextual Notes

Participants are navigating through the assumptions related to momentum conservation and the conditions of the collision, including the initial states of the objects involved.

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Homework Statement



An arrow of mass 100 g is fired with an initial horizontal velocity of 40 m s–1 to the right at an apple of mass 80 g that is initially at rest on a horizontal surface. When the arrow strikes the apple, the two objects stick together. What is the common velocity of the arrow and apple after the impact?

Homework Equations


Momentum = mass * velocity


The Attempt at a Solution



Initial Momentum of the Arrow
p=m*v
=(.1)(40)
= 4

4=.08* v
therefore v= 50 m/s

the answer says it's 22m/s
 
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4=.08* v
therefore v= 50 m/s

This is wrong.
When the arrow strikes the apple, the two objects stick together.
So rewrite the above equation.
 


I don't get it
If the momentum is 0 then the velocity is 0
 


Momentum after impact = ( 0.1 + 0.08)*v
 


m1v1 = (m1 + m2)v
 

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