What is the correct force exerted by the seat in a pulley and force problem?

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In a pulley problem involving a 612 N person and a 16.0 N seat, the person pulls on a massless rope with a force of 348 N. The correct calculation for the force exerted by the seat on the person involves considering the net forces acting on the system, including the tension from the rope and the weight of the person. The equation T + F_seat - mg = ma leads to the conclusion that the force exerted by the seat is 330 N, not 332 N as initially calculated. This highlights the importance of correctly accounting for all forces in the system to determine the accurate force exerted by the seat. Understanding these dynamics is crucial for solving similar physics problems effectively.
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Here's the question:
A 612 N person is sitting in a 16.0 N seat with one end of a massless rope attached to the seat. The rope runs over an ideal pulley, and the other end of it is in the person's hand. The person pulls the loose end of the rope with a force of 348 N.

The problems asks to determine the acceleration of the person (1.06 m/s^2) and the force that the seat exerts on the person.

I found the force exerted by the seat on the person to be 332 N (348 N - 16.0 N), but that is not the correct answer. What am I missing?
 
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Start by figuring out the acceleration of "seat + person". What forces act on that system? (Hint: What force does the rope exert on that system? How many places does the rope attach?)
 
Got it.
The forces exerted on the person are the tension of the rope in the upward direction, the force of the seat in the upward direction, and its weight (mg) in the downward direction. So,

T + F_seat + (-mg) = ma
348 N + F_seat - 612 N = (62.45 kg)(1.06 m/s^2)
F_seat = 330 N

Thanks!
 
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