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What is the cross section area of the water?

  1. May 3, 2012 #1
    what is the cross section area of the water??

    1. The problem statement, all variables and given/known data
    Determine an expression for the cross sectional area A of the fluid in the tank as a function of D and H.


    2. Relevant equations
    A=pi*r2

    3. The attempt at a solution
    i try to let the radius equal to the height but then the fluid's height goes lower, it doesn't form a circle anymore. So i have no ideas how to do this.Please help.
     

    Attached Files:

  2. jcsd
  3. May 3, 2012 #2

    Mark44

    Staff: Mentor

    Re: what is the cross section area of the water??

    What is the shape of the tank? In your drawing, the cross-section is half a circle, but is the tank spherical or cylindrical or what? To get an expression for the cross-sectional area of the water, you need to know the shape of the tank.
     
  4. May 3, 2012 #3

    sharks

    User Avatar
    Gold Member

    Re: what is the cross section area of the water??

    I believe the tank is a half sphere? So, the volume of the sphere is: [tex]\frac{2}{3}\pi r^3[/tex]
     
  5. May 3, 2012 #4

    Mark44

    Staff: Mentor

    Re: what is the cross section area of the water??

    Correction added.
    Nothing in the OP's post says anything about the actual shape of the tank.
     
  6. May 3, 2012 #5

    sharks

    User Avatar
    Gold Member

    Re: what is the cross section area of the water??

    If you click on the attached picture in the first post, it does say "hemispherical" in the lower-right corner. In that case, H= r (radius if sphere) and D = 2r (diameter).
     
  7. May 3, 2012 #6

    Mark44

    Staff: Mentor

    Re: what is the cross section area of the water??

    So it does. I missed that.
     
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