What Is the Diameter of a Nichrome Wire in a Circuit?

AI Thread Summary
The discussion focuses on calculating the diameter of a nichrome wire connected to a 1.8 V battery with a current of 2.1 A. Using the resistance formula R = ρL/A and Ohm's law V = IR, the resistance is determined to be 0.86 Ohms. The cross-sectional area A is calculated as 2.21 x 10^-7 m², leading to the radius being approximately 0.000265 m. Converting this to millimeters results in a radius of about 0.265 mm, and since the diameter is twice the radius, the final diameter is approximately 0.53 mm. The solution emphasizes the importance of distinguishing between diameter and radius in the calculations.
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Homework Statement


A 19-cm-long nichrome wire is connected across the terminals of a 1.8 V battery. If the current in the wire is 2.1 A, what is the wire's diameter in mm?


Homework Equations


R = Rho*L
--------
A
v=ir


The Attempt at a Solution


rho for this = 100 e -8.

V=IR
TF,
R = .86 Ohms
100 e -8(.19)
-------------
.86

= 2.21 e -7 m^2

A = pi * r^2

(2.21 e -7/pi)^.5 = r

= 0.000265229118 m.

= 0.265229118 millimeters
 
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Note the question is asking for the wire's diameter, not its radius.
 
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