What is the Diameter of a Tungsten Wire with a Weight of 1.72 mg?

AI Thread Summary
The discussion revolves around calculating the diameter of a tungsten wire weighing 1.72 mg and measuring 200 mm in length. Initial calculations suggested a diameter of 0.13 mm, but further analysis revealed a mistake in converting milligrams to kilograms, which should be 0.000172 kg instead of 0.00172 kg. Using the correct density of tungsten (19250 kg/m3), the volume was recalculated, leading to a revised diameter of approximately 0.0477 mm. Participants emphasize the importance of accurate unit conversion and applying the correct formulas for density and volume. The conversation highlights common pitfalls in physics calculations, particularly regarding mass and weight.
Virsnieks
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Homework Statement



If we know, that 200 mm of tungsten wire weight`s 1.72 mg, then what is the diameter of this wire

Homework Equations





The Attempt at a Solution



I by my self came to the conclusion, that the answer is 0.13 mm. But if I take in accordance, that my Algebra and Physics is more than poor... may someone could calculate and prof this.

Thx
 
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"If we know, that 200 mm of tungsten wire weight`s 1.72 mg, then what is the diameter of this wire"

Grams are mass, not weight.

A wire is a long, thin cylinder. Compute volume in terms of diameter, then mass. Solve for diameter.
 
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Virsnieks said:

Homework Statement



If we know, that 200 mm of tungsten wire weight`s 1.72 mg, then what is the diameter of this wire

Homework Equations





The Attempt at a Solution



I by my self came to the conclusion, that the answer is 0.13 mm. But if I take in accordance, that my Algebra and Physics is more than poor... may someone could calculate and prof this.

Thx
I calculate something different. If you show us your actual calculations, we can help figure out what went wrong.
 
So I try`d to calculate it one more time this morning whis a fresh head and got some different:
My Idea was to use formula for Desity, to get the Volume and then change the formula for cilinder volumen V=p*r2*h, for getting the radius

200 mm = 0.2 m
1.72mg= 0.00172 kg
Denisty of tungsten = 19250 kg/m3

1. Step. Density = Mass/Volume, so Volume = mass/density

Volume = 0.00172/19250 = 0.000000008935 m3

2. Step. V=p*r2*h; 0.000000008935=3.14*r2*0.2

r=SQRT of 0.000000008935/3.14*0.20
r= 0,0000238559904479939 m
r=0.02385599 mm or the Diameter then would be 0.04771198 mm. This looks better...
 
Last edited:
1.72mg= 0.00172 kg

You are saying that 1.72 milligrams is 0.00172 kilogram??
 
0.000172 kg - one zero missed... everything else should be correct.
 
Virsnieks said:
0.000172 kg - one zero missed... everything else should be correct.

Try again.
 
Virsnieks said:
0.000172 kg - one zero missed... everything else should be correct.

No - mg is not g. What does the 'm' stand for?
 
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