What is the Direction of the Velocity of a Particle in a Rotating Tube?

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Ok so I have this tube of length 2R that rotates in the horizontal xy plane with constant angular velocity \omega about the z axis. And there is this particle of mass m that is released a distance R from the origin. Assuming the tube is frictionless I need to find the direction of the velocity of the particle just as it leaves the tube?

Picture:
[PLAIN]http://img696.imageshack.us/img696/4020/tubev.png

Any help is appreciated!
 
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I am telling Sri about this in class tomorrow


But the answer is v0/r
 
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