What Is the Distance Between the Slits in Young's Double-Slit Experiment?

AI Thread Summary
In Young's double-slit experiment, the distance between the slits is calculated using the formula d sin θ = n λ, where λ is the wavelength of light (632.8 nm) and θ is the angle to the second side maximum (0.45 degrees). The calculation yields a distance d of approximately 1487.36 nm, assuming n is 2 for the second maximum. A correction is noted regarding the angle, clarifying that 0.45 degrees is not equivalent to 45 degrees. The discussion confirms the calculation method but highlights the importance of accurate angle interpretation. Accurate values are crucial for reliable results in such experiments.
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Homework Statement


When two parallel slits are illuminated with monochromatic light of wavelength 632.8 nm, the angle between the center of the central maximum and the center of the second side maximum is .45 degrees. What is the distance between the parallel slits.


Homework Equations



d sin θ = n λ



The Attempt at a Solution



d=2(632.8 nm)/sin 45 degrees

d = 1487.36 nm

My "d" value seems a bit odd, so I wanted to make sure I did this correctly. Note that I assigned "2" as the value of n because the problem said "second side maximum". Thank you.
 
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.45 degrees and 45 degrees are not the same thing. Apart from that (and the resulting wrong value for d), it looks fine.
 
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Okay. Thank you for the confirmation!
 

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