What is the Dot Product of a Cutting Tool Under Microprocessor Control?

[burhan619]

Homework Statement

A cutting tool under microprocessor control has several forces acting on it. One force is \vec{F}=-αxy²\hat{j}, a force in the negative y-direction whose magnitude depends on the position of the tool. The constant is α=2.50 N/m³. Consider the displacement of the tool from the origin to the point x=3.00m, y=3.00m.

(a) Calculate the work done on the tool by \vec{F} if this displacement is along the straight line y=x that connects these two points.

Homework Equations

W=∫\vec{F}\cdotd\vec{l}

The Attempt at a Solution

I'm trying to use the equation above, so here's what I know:

d\vec{l}=dx\hat{i}+dy\hat{j}
\vec{F}=-αxy²\hat{j}

Since it's the dot product,
\vec{F}\cdotd\vec{l}=dx+-αxy²dy.

I'm confused as to why the right side of that equation is equal to -αy³dy, as the textbook solution suggests. Any help is appreciated.

 

[Andrew Mason]

I'm confused as to why the right side of that equation is equal to -αy³dy, as the textbook solution suggests. Any help is appreciated.

If x = y then -axy^2 = -ay^3

The dot product of the two vectors is:

\vec{a} \cdot \vec{b} = ab\cos\theta

where \theta is the angle between the two vectors.

AM